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(x-3)(x-5)=x^2-7x-15
We move all terms to the left:
(x-3)(x-5)-(x^2-7x-15)=0
We get rid of parentheses
-x^2+(x-3)(x-5)+7x+15=0
We multiply parentheses ..
-x^2+(+x^2-5x-3x+15)+7x+15=0
We add all the numbers together, and all the variables
-1x^2+(+x^2-5x-3x+15)+7x+15=0
We get rid of parentheses
-1x^2+x^2-5x-3x+7x+15+15=0
We add all the numbers together, and all the variables
-1x+30=0
We move all terms containing x to the left, all other terms to the right
-x=-30
x=-30/-1
x=+30
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